Combination of Resistors: Practice Problem & Solution

Solution Explained:

To solve this problem, we apply the core principles of Combination of Resistors. Understanding the underlying formula is key to arriving at the correct answer below:

Between any two terminals of the triangle, two $4 \Omega$ resistors are in series, giving $8 \Omega$. This combination is in parallel with the third $4 \Omega$ resistor. Equivalent resistance $R_{eq} = \frac{8 \times 4}{8 + 4} = \frac{32}{12} = 8/3 \Omega$.