Solution:
In a free-falling lift, the effective acceleration due to gravity is zero ($ g_{eff} = g - g = 0 $). Since frequency $ f = \frac{1}{2\pi}\sqrt{\frac{g_{eff}}{l}} $, the frequency becomes zero.
In a free-falling lift, the effective acceleration due to gravity is zero ($ g_{eff} = g - g = 0 $). Since frequency $ f = \frac{1}{2\pi}\sqrt{\frac{g_{eff}}{l}} $, the frequency becomes zero.
Leave a Reply