Rankers Physics

Spring Block System: Practice Problem & Solution

The period of oscillation of a mass $M$ suspended from a spring of negligible mass is $T$. If along with it another mass $M$ is also suspended, the period of oscillation will now be: (2010 Pre)
$\sqrt{2}T$
$T$
$\frac{T}{\sqrt{2}}$
$2T$

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Spring Block System. Understanding the underlying formula is key to arriving at the correct answer below:

$T = 2\pi\sqrt{\frac{M}{k}}$. When another mass $M$ is suspended, total mass is $2M$. New period $T' = 2\pi\sqrt{\frac{2M}{k}} = \sqrt{2}T$.

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