Rankers Physics

Electric Field: Practice Problem & Solution

Four charges are placed on the circumference of a circle of radius R, 90° apart as shown in the figure . The electric field strength at the centre of the circle is Electric Field diagram: Four charges are placed on the circumference of
\frac{1}{4\pi\varepsilon_{0}}\frac{2\sqrt{5}Q}{R^{2}}, making angle tan^{-1}2 with the -ve axis
\frac{1}{4\pi\varepsilon_{0}}\frac{2\sqrt{5}Q}{R^{2}}, making angle tan^{-1}2 with the +ve axis
\frac{1}{4\pi\varepsilon_{0}}\frac{4\sqrt{2}Q}{R^{2}}, making angle tan^{-1}\frac{1}{2} with the -ve axis
\frac{1}{4\pi\varepsilon_{0}}\frac{4\sqrt{2}Q}{R^{2}}, making angle tan^{-1}\frac{1}{2} with the +ve axis

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Similar Practice Questions

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1. Assertion: Sharper is the curvature of spot on a charged body lesser will be the surface charge density at that point. Reason: Electric field is non-zero inside a charged conductor.
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