Uncategorized: Practice Problem & Solution
In a rocket, fuel burns at the rate of \( 1 \text{ kg/s} \). This fuel is ejected from the rocket with a velocity of \( 60 \text{ km/s} \). This exerts a force on the rocket equal to: (1994)
Solution Explained:
To solve this problem, we apply the core principles of Uncategorized. Understanding the underlying formula is key to arriving at the correct answer below:
Thrust force \( F = v_e \frac{dM}{dt} \). Given exhaust velocity \( v_e = 60 \text{ km/s} = 60000 \text{ m/s} \). Given rate of fuel consumption \( \frac{dM}{dt} = 1 \text{ kg/s} \). \( F = 60000 \text{ m/s} \times 1 \text{ kg/s} = 60000 \text{ N} \).
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