Uncategorized: Practice Problem & Solution
If a body A of mass M is thrown with velocity v at an angle of \(30°\) to the horizontal and another body B of the same mass is thrown with the same speed at an angle of \(60°\) to the horizontal, the ratio of horizontal range of A to B will be: (1992, 90)
Solution Explained:
To solve this problem, we apply the core principles of Uncategorized. Understanding the underlying formula is key to arriving at the correct answer below:
Concept: Horizontal range for complementary angles.
Formula: \(R = (u^2 sin 2theta) / g\).
For A, \(theta_A = 30°\). For B, \(theta_B = 60°\).
Since \(theta_A + theta_B = 90°\), they are complementary angles. Range is same if initial speed is same. Thus, \(R_A : R_B = 1:1\).
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