Solution:
The speed squared is \(v^2 = 6^2 + (-8)^2 = 100\text{ m}^2\text{/s}^2\). The kinetic energy is \(KE = \frac{1}{2}mv^2 = \frac{1}{2}(0.4)(100) = 20\text{ J}\).
A particle of mass \(0.4\text{ kg}\) is moving with a velocity of \((6\hat{i} - 8\hat{j})\text{ m/s}\), then the kinetic energy of the particle is
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