First Law of Thermodynamics for Isobaric Process – Rankers Physics
Topic: Thermal Physics
Subtopic: Thermodynamics

First Law of Thermodynamics for Isobaric Process

For \(n\) mole of an ideal gas, the correct equation of \(1^{\text{st}}\) law of thermodynamics corresponding to isobaric process will be (symbols have their usual meanings)
\(Q = \Delta U + P\Delta V\)
\(Q = \Delta U + nR\Delta T\)
\(Q = \Delta U\)
Both (1) and (2)

Solution:

According to the first law of thermodynamics, \(Q = \Delta U + W\). For an isobaric process, the work done is \(W = P\Delta V = nR\Delta T\). Therefore, both equations (1) and (2) are correct representation.

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