Screw Gauge: Practice Problem & Solution

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Screw Gauge. Understanding the underlying formula is key to arriving at the correct answer below:

Least Count (LC) = \(0.01 \text{mm}\), Number of divisions on circular scale = \(50\). The formula for LC is: LC = Pitch / Number of divisions. Therefore, Pitch = LC \(\times\) Number of divisions = \(0.01 \text{mm} \times 50 = 0.5 \text{mm}\).