Unit And Dimensions - NEET Physics Questions
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Unit And Dimensions

Question 101: easy

A screw gauge gives the following readings when used to measure the diameter of a wire
Main scale reading: \(0 \text{mm}\)
Circular scale reading: \(52 \text{divisions}\)
Given that \(1 \text{mm}\) on main scale corresponds to \(100 \text{divisions}\) on the circular scale. The diameter of the wire from the above data is:

[NEET 2020]

1. \(0.026 text{cm}\)
2. \(0.26 text{cm}\)
3. \(0.052 text{cm}\)
4. \(0.52 text{cm}\)
View Answer

Pitch = \(1 \text{mm}\), Number of divisions = \(100\). Least Count (LC) = Pitch / Number of divisions = \(1 \text{mm} / 100 = 0.01 \text{mm}\). Total reading = MSR + (CSR \(\times\) LC) = \(0 \text{mm} + (52 \times 0.01 \text{mm}) = 0.52 \text{mm}\). Convert to cm: \(0.52 \text{mm} = 0.052 \text{cm}\).

Question 102: easy

A screw gauge has least count of \(0.01 \text{mm}\) and there are \(50 \text{divisions}\) in its circular scale. The pitch of the screw gauge is:

[NEET 2020]

1. \(0.25 \text{mm}\)
2. \(0.5 \text{mm}\)
3. \(1.0 \text{mm}\)
4. \(0.01 \text{mm}\)
View Answer

Least Count (LC) = \(0.01 \text{mm}\), Number of divisions on circular scale = \(50\). The formula for LC is: LC = Pitch / Number of divisions. Therefore, Pitch = LC \(\times\) Number of divisions = \(0.01 \text{mm} \times 50 = 0.5 \text{mm}\).

Question 103: easy

A student measured the diameter of a small steel ball using a screw gauge of least count \(0.001 \text{cm}\). The main scale reading is \(5 \text{mm}\) and zero of circular scale division coincides with \(25 \text{divisions}\) above the reference level. If screw gauge has a zero error of \(-0.004 \text{cm}\), the correct diameter of the ball is :

[NEET 2018]

1. \(0.053 \text{cm}\)
2. \(0.525 \text{cm}\)
3. \(0.521 \text{cm}\)
4. \(0.529 \text{cm}\)
View Answer

Least Count (LC) = \(0.001 \text{cm}\). Main Scale Reading (MSR) = \(5 \text{mm} = 0.5 \text{cm}\). Circular Scale Reading (CSR) = \(25 \text{divisions}\). Observed Reading = MSR + (CSR \(\times\) LC) = \(0.5 \text{cm} + (25 \times 0.001 \text{cm}) = 0.525 \text{cm}\). Correct Reading = Observed Reading - Zero Error = \(0.525 \text{cm} - (-0.004 \text{cm}) = 0.525 \text{cm} + 0.004 \text{cm} = 0.529 \text{cm}\).

Question 104: moderate

The mechanical quantity, which has dimensions of reciprocal of mass (\(\text{M}^{-1}\)) is

1. Torque
2. Gravitational constant
3. Angular momentum
4. Coefficient of thermal conductivity
View Answer

The dimensions of the Gravitational constant \(G\) are \([\text{M}^{-1}\text{L}^3\text{T}^{-2}]\). Thus, it has the dimensions of reciprocal of mass.

Question 105: moderate

The diameter of a spherical bob, when measured with vernier callipers yielded the following values: 3.33 cm, 3.32 cm, 3.34 cm, 3.33 cm and 3.32 cm. The mean diameter to appropriate significant figures is:

1. 3.33 cm
2. 3.32 cm
3. 3.328 cm
4. 3.3 cm
View Answer

The mean of the values is \[\frac{3.33 + 3.32 + 3.34 + 3.33 + 3.32}{5} = 3.328 \text{cm}\]. Since the measurements are up to two decimal places, the rounded final result should also have two decimal places: 3.33 cm.

Question 106: easy

Which of the following statement is not true?

1. Pressure is a vector quality
2. Relative density is a scalar quantity
3. Coefficient of viscosity is a scalar quantity
4. Surface tension is a scalar quantity
View Answer

Pressure is defined as force per unit area, where the force is perpendicular to the surface. Since it acts equally in all directions, pressure is a scalar quantity.

Question 107: easy

Following observations were taken with a vernier calliper while measuring the length of a cylinder: \(3.29 \text{cm}\), \(3.28 \text{cm}\), \(3.29 \text{cm}\), \(3.31 \text{cm}\), \(3.28 \text{cm}\). The most accurate length of the cylinder will be

1. \(3.28 \text{cm}\)
2. \(3.29 \text{cm}\)
3. \(3.32 \text{cm}\)
4. \(3.21 \text{cm}\)
View Answer

The most accurate value is the mean value of the observations. Mean length = \[\frac{3.29 + 3.28 + 3.29 + 3.31 + 3.28}{5} = \frac{16.45}{5} = 3.29 \text{cm}\].

Question 108: moderate

Consider the given statements:


Statement A: Measured value by any measuring instrument has some error.


Statement B: A measurement can have more accuracy and less precision and vice-versa.


Statement C: The magnitude of the difference between the true value of the quantity and the individual measured value is called relative error of measurement.


Choose the correct option.

1. Only statement A is true
2. Only statement B is true
3. Both statements A and C are true
4. Both statements A and B are true
View Answer

Statements A and B are correct properties of measurements. Statement C is incorrect because the described quantity is the absolute error, not the relative error.