Dimensions - NEET Physics Questions
Question 61: easy

The time dependence of a physical quantity (p) is given by \(p = p_0 \text{exp } (-\alpha t^2)\), where (alpha) is constant and (t) is the time. The constant \(\alpha\):

[1993]

 

1. Is dimensionless
2. Has dimensions \(T^{-2}\)
3. Has dimensions \(T^2\)
4. Has dimensions of \(p\)
View Answer

For \(\text{exp }(-\alpha t^2)\) to be dimensionless, \(\alpha t^2\) must be dimensionless. \([\alpha][t^2] = [M^0L^0T^0]\). Since \([t] = [T]\), \([\alpha][T^2] = [1]\). Thus, \([\alpha] = [T^{-2}]\).

Question 62: easy

(P) represents radiation pressure, (c) represents speed of light and (S) represents radiation energy striking per unit area per sec. The non-zero integers (x, y, z) such that \(P^x S^y c^z\) is dimensionless are:

[1992]

1. (x = 1, y = 1, z = 1)
2. (x = -1, y = 1, z = 1)
3. (x = 1, y = -1, z = 1)
4. (x = 1, y = -1, z = -1)
View Answer

Dimensions: \(P = [ML^{-1}T^{-2}]\), \(c = [LT^{-1}]\), \(S = [MT^{-3}]\). For \(P^x S^y c^z\) to be dimensionless, powers of M, L, T must be zero. \(M: x+y=0\). \(L: -x+z=0\). \(T: -2x-3y-z=0\). Solving gives \(y=-x\) and \(z=x\). Taking \(x=1\) yields \(y=-1\), \(z=1\).

Question 63: easy

The frequency of vibration (f) of a mass (m) suspended from a spring of spring constant (k) is given by a relation \(f = a.m^x k^y\), where (a) is a dimensionless constant. The values of (x) and (y) are:

[1990]

1. \(x = \frac{1}{2}, y = \frac{1}{2}\)
2. \(x = -\frac{1}{2}, y = \frac{1}{2}\)
3. \(x = \frac{1}{2}, y = -\frac{1}{2}\)
4. \(x = -\frac{1}{2}, y = -\frac{1}{2}\)
View Answer

Frequency \(f = [T^{-1}]\). Mass (m = [M]). Spring constant \(k = [MT^{-2}]\). Comparing dimensions of \(f = m^x k^y\): \([T^{-1}] = [M]^x [MT^{-2}]^y = [M^{x+y} T^{-2y}]\). Solving (x+y=0) and (-2y=-1) gives (y = 1/2) and (x = -1/2).

Question 64: moderate

The mechanical quantity, which has dimensions of reciprocal of mass (\(\text{M}^{-1}\)) is

1. Torque
2. Gravitational constant
3. Angular momentum
4. Coefficient of thermal conductivity
View Answer

The dimensions of the Gravitational constant \(G\) are \([\text{M}^{-1}\text{L}^3\text{T}^{-2}]\). Thus, it has the dimensions of reciprocal of mass.

Question 65: easy

Choose the quantities that are dimensionless among the following.

1. \(\frac{\text{Torque}}{\text{Force}}\)
2. \(\frac{\text{Torque}}{\text{Work}}\)
3. \(\frac{\text{Work}}{\text{Energy}}\)
4. Both (2) and (3)
View Answer

Torque, work, and energy all have the same dimensions \([ML^2T^{-2}]\). Hence, \(\frac{\text{Torque}}{\text{Work}}\) and \(\frac{\text{Work}}{\text{Energy}}\) are both dimensionless, while \(\frac{\text{Torque}}{\text{Force}}\) has the dimension of length.

Question 66: easy

Two physical quantities \(P\) and \(Q\) have different dimensions. The mathematical operation that is not possible among the following are

1. \(\frac{P}{Q}\)
2. \(PQ\)
3. \(P + Q\)
4. Both (1) and (2)
View Answer

According to the principle of homogeneity of dimensions, only quantities with identical dimensions can be added or subtracted. Multiplication and division of different physical quantities are allowed.