NEET Physics Question - Work Energy and Power - Work Done by Constant and Variable Forces

Rankers Physics

Topic: Work Energy and Power

Subtopic: Work Done by Constant and Variable Forces

A force of (5 + 3x) N, acting on a body of mass 20 kg along the x-axis, displaces it from x = 2 m to x = 6 m. The work done by the force is

20 J

48 J

68 J

86 J

Work Done by Variable force is ∫F.dx, So

W= ∫(5 + 3x).dx= 5x+3x²/2

Using Limits from x=2 to x=6 we get

W= 68 J