Solution:
Work Done by Variable force is ∫F.dx, So
W= ∫(3x² –2x + 7).dx=[3x³/3-2x²/2+7x]= [x³-x²+7x]
Using Proper limits from x=0 to x= 5, we get
W= 125-25+35=135 J
A particle moves along the x-axis from x = 0 to x = 5 m under the influence of a force F (in N) given by F = 3x² –2x + 7. Calculate the work done by this force.
Leave a Reply