Solution:
From Principal of conservation of Energy in absence of non-conservative forces,
Ui+ Ki= Uf+ Kf
⇒mg(6) +0 = mg(1) + ½mv²
⇒mg(5)= ½mv²
⇒ v²=100 or v =10 m/s
A child on a swing is 1 m above the ground at the lowest point and 6 m above the ground at the highest point. The horizontal speed of the child at the lowest point of the swing is approximately
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