A body is released from position A as shown in figure. The speed of body at position B is10 m/s10√2 m/s20 m/s20√2 m/sSolution:From Principal of Conservation of Energy Ui + Ki= Uf+ Kf ⇒ mg(50) + 0 = mg(10) + ½ m v² ⇒ v² = 800 ⇒ v = 20√2 m/s
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