Solution:
Given U = 20 + (x – 2)2
For Equilibrium , dU/dx = 2 (x-2) =0, So, x=2 is the point of Equilibrium.
d²U/dx²= 2 >0 so, x= 2 is the point of stable equilibrium.
U min = 20 J
As Total Energy is 36 J.
U min + K max = 36 J
⇒ K max = 16 J
The potential energy of a particle oscillating on x-axis is given as : U = 20 + (x – 2)2 Joules. If total mechanical energy of the particle is 36 J, then its maximum kinetic energy is:
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