Rankers Physics
Topic: Work Energy and Power
Subtopic: Potential Energy & Equilibrium

A cubical vessel of height 1 m is full of water. The minimum work done in taking water-out from vessel will be
5000 J
10000 J
5 J
10 J

Solution:

As side length of cubical tank is 1 m. Volume is 1 m³. Volume of water in 1 m³ is 1000 lit and mass will be 1000 kg.

Height of center of mass of the tank will be 1/2 m.

Potential Energy = 1000 ×10 × 1/2 = 5000 J

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