NEET Physics Question - Thermal Physics

In some old science notes we come across a temperature scale called Z scale (gargi scale) on which boiling point of water is 65ºZ and freezing point is –14ºZ. It is found that a change of 1º on Z scale corresponds to change of xº on Fahrenheit scale. Then x is :

\[ \frac{79}{180}\]

\[ \frac{180}{79}\]

\[ \frac{79\times 32}{180}\]

\[ \frac{180}{79}\times \frac{1}{32}\]

Solution:

To find \( x \), we need to compare the Z scale with the Fahrenheit scale.

1. Range on the Z scale:
\[
65^\circ Z - (-14^\circ Z) = 65 + 14 = 79^\circ Z
\]

2. Range on the Fahrenheit scale:
The boiling and freezing points of water are 212ºF and 32ºF, respectively, so:
\[
212^\circ F - 32^\circ F = 180^\circ F
\]

3. Relationship between scales:
A change of \( 79^\circ Z \) corresponds to \( 180^\circ F \). Therefore:
\[
x = \frac{180}{79}
\]

So, \( x = \frac{180}{79} \).

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Solution:

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