
Solution:
Both the diodes are forward biased so current will flow through the circuit
i= 10/4.5= 20/9 mA
V0= i R= (20/9)×3.3 Volt= 6.6 volt
Both the diodes are forward biased so current will flow through the circuit
i= 10/4.5= 20/9 mA
V0= i R= (20/9)×3.3 Volt= 6.6 volt
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