Rankers Physics
Topic: Semiconductor Physics
Subtopic: P-N Junction Diode and its applications

If break down voltage of zener diode is 6 V then value of I2 will be :   Image related to
18 mA
24 mA
6 mA
Zero

Solution:

Voltage across 500 ohm resistor = 12 Volt

I = 12/500 = 24 mA

I 1 =  6/1000= 6mA

I2= I - I1= (24-6 )mA= 18 mA

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