Rankers Physics
Topic: Semiconductor Physics
Subtopic: P-N Junction Diode and its applications

A p–n photodiode is made of a material with a band gap of 2.0 eV. The minimum frequency of the radiation that can be absorbed by the material is nearly :
\[1\times 10_{14} Hz\]
\[20\times 10_{14} Hz\]
\[10\times 10_{14} Hz\]
\[5\times 10_{14} Hz\]

Solution:

Energy of EM wave E = hυ

⇒ 2 eV = 6.626 × 10^-34×υ

⇒  \[v= 5\times 10_{14} Hz\]

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