Solution:
ω = ω0 + α.t
0= (60 × 2π /60) + α.60
⇒ α = - π/30
Torque = I α = (2× π/30) = (π/15) N-m
A wheel having moment of inertia 2 kg-m² about its vertical axis, rotates at the rate of 60 rpm about this axis. The torque which can stop the wheel's rotation in one minute would be
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