Solution:
As the object slides with constant speed friction force is balancing mgsinθ. Torque of Normal reaction and friction force about centre of object will cancel each other.
τ=mg.sinθ × a/2 = (mg a sinθ)/2
A cubical block of mass m and edge a slides down a rough inclined plane of inclination θ with a uniform speed. Find the torque of the normal force acting on the block about its centre
Leave a Reply