A wire of mass m and length L is bent in the form of a circular ring. The moment of inertia of the ring about its axis ismL²mL²/ 4π²mL²/ 2π²mL²/ 8π²Solution:Let the radius of Ring formed is R. Then 2πR= L ⇒ R = L/2π Moment of Interia= m (L/2π)²= mL²/ 4π²
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