Solution:
\[ x= A sin\left( \omega t \right) \]
\[ \frac{A}{2}= A sin\left( \omega t \right) \]
\[ \frac{1}{2}= sin\left( \omega t \right) \]
\[ \frac{\Pi}{6}= \omega t =\frac{2\Pi}{T}t = \frac{2\Pi}{3}t \]
\[ t= \frac{1}{4}s \]
A periodic time of a body executing simple harmonic motion is 3s. After how much interval from time t = 0, its displacement from mean position will be half of its amplitude ?
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