Solution:
y = 3sin π/2 (50t - Φ)
\[ \frac{\partial y}{\partial t}= 3 \times \frac{\Pi}{2}\times 50 cos(π/2 (50t - Φ))\]
Maximum speed = 75 π
The equation of a simple harmonic motion is given by, y = 3sin π/2 (50t - Φ), where y is in metres and t is in sec, the maximum particle velocity in ms–¹ is :
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