Rankers Physics
Topic: Oscillation
Subtopic: Equation of SHM

Two simple harmonic motions of angular frequency 10rad/sec and 100 rad s–¹ have the same displacement amplitude. The ratio of their maximum acceleration is
1 : 10³
\[ 1:10^{4}\]
1 : 10
1 : 10²

Solution:

Solution:

1. Maximum Acceleration in SHM is given by:
\[
a_{\text{max}} = \omega^2 A
\]

2. Ratio of Maximum Accelerations:
\[
\frac{a_{\text{max}_2}}{a_{\text{max}_1}} = \frac{\omega_2^2 A}{\omega_1^2 A} = \frac{\omega_2^2}{\omega_1^2} = \frac{(100)^2}{(10)^2} = \frac{10000}{100} = 100
\]

Answer:
The ratio of their maximum accelerations is \( 1 : 100 \) or \( 1 : 10^2 \).

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