NEET Magnetic Field Due to Circular Current Carrying Wire MCQs & PYQs

Practice NEET Magnetic Field Due to Circular Current Carrying Wire Questions

Question 11:

moderate

A wire is bent in the form of a circular arc with a straight portion AB. Magnetic induction at O
when current I is flowing in the wire, is :

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Question 12:

moderate

A wire carrying current I has the configuration as shown in Fig. Two semi-infinite straight
sections both tangent to the same circle are connected by a circular arc of central angle θ,
along the circumference of the circle, with all sections lying in the same plane. If the magnetic
field at the centre of the circle is zero, then θ is:

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Question 13:

moderate

Radius of the current carrying coil is R. If magnetic field at any point on the axis of the coil is \[Bx=\frac{B_{0}}{64}\] then find out axial distance of this point :

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Question 14:

moderate

Three long, straight and parallel wires carrying currents are arranged as shown in figure. The force experienced by 10 cm length of wire Q is :

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Question 15:

moderate

Same current i = 2A is flowing in a wire frame as shown in figure. The frame is a combination of two equilateral triangles ACD and CDE of side 1m. It is placed in uniform magnetic field B = 4T acting perpendicular to the plane of frame. The magnitude of magnetic force acting on the frame is :

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Question 16:

moderate

A helium nucleus is moving in a circular path of radius $0.8\text{ m}$. If it takes $2\text{ sec}$ to complete one revolution, the magnetic field produced at the centre of the circle is:

Current is $I = \frac{q}{T} = \frac{2e}{2} = e = 1.6 \times 10^{-19}\text{ A}$. The magnetic field at the centre is $B = \frac{\mu_0 I}{2R} = \frac{\mu_0 (1.6 \times 10^{-19})}{2(0.8)} = \mu_0 \times 10^{-19}\text{ T}$.

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Question 17:

moderate

A long wire carrying a steady current is bent into a circular loop of one turn. The magnetic field at the center of the loop is B. It is then bent into a circular coil of n turns. The magnetic field at the center of this coil of n turns will be:

(2016 – II)

For a single turn loop, radius $R = \frac{L}{2\pi}$ and $B = \frac{\mu_0 i}{2R}$. When bent into $n$ turns, the new radius is $R' = \frac{R}{n}$. The magnetic field becomes $B' = \frac{\mu_0 n i}{2R'} = n^2 B$.

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Question 18:

moderate

An electron moving in a circular orbit of radius r makes n rotations per second. The magnetic field produced at the center has magnitude:

(2015)

The current produced by the revolving electron is $i = qf = ne$. The magnetic field at the center of a circular loop of radius $r$ carrying current $i$ is $B = \frac{\mu_0 i}{2r} = \frac{\mu_0 n e}{2r}$.

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Question 19:

moderate

Two similar coils of radius R are lying concentrically with their planes at right angles to each other. The currents flowing in them are I and 2I, respectively. The resultant-magnetic field induction at the center will be:

(2012 Pre)

The magnetic fields due to the two perpendicular coils are $B_1 = \frac{\mu_0 I}{2R}$ and $B_2 = \frac{\mu_0 (2I)}{2R} = \frac{\mu_0 I}{R}$. Since their planes are at right angles, the fields are perpendicular, so $B_{\text{res}} = \sqrt{B_1^2 + B_2^2} = \frac{\sqrt{5}\mu_0 I}{2R}$.

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Question 20:

moderate

Charge q is uniformly spread on a thin ring of radius R. The ring rotates about its axis with a uniform frequency f Hz. The magnitude of magnetic induction at the center of the ring is:

(2011 Mains)

The equivalent current is $i = qf$. The magnetic induction at the center of a circular ring of radius $R$ carrying current $i$ is $B = \frac{\mu_0 i}{2R} = \frac{\mu_0 q f}{2R}$.

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