NEET Physics Question - Laws of Motion

If the coefficient of friction between the block of mass 5 kg and wall is 0.5, then minimum force F required to hold the block with the wall is (g = 10 m/s²) Image related to

10 N

100 N

40 N

50 N

Solution:

\[
\text{Given:} \quad m = 5 \text{ kg}, \quad g = 10 \text{ m/s}^2, \quad \mu = 0.5
\]

\text{Normal force:}
\[
N = F
\]

\text{Friction force:}
\[
f = \mu N = \mu F
\]

\text{For equilibrium:}
\[
\mu F = mg
\]

\text{Substituting values:}
\[
0.5 F = 5 \times 10
\]

\[
0.5 F = 50
\]

\[
F = \frac{50}{0.5} = 100 \text{ N}
\]

\textbf{Final Answer:}
\[
\mathbf{F = 100 N}
\]

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Solution:

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