NEET Physics Question - Kinematics - Relative Motion in One Dimension

Rankers Physics

Topic: Kinematics

Subtopic: Relative Motion in One Dimension

A taxi leaves the station X for station Y every 10 minutes. Simultaneously, a taxi leaves the station Y also for station X every 10 minutes. The taxis move at the same constant speed and go from X to Y or vice-versa in 2 hours. How many taxis coming from the other side will each taxi meet enroute from Y to X ?

10

11

12

23

Solution:

Each taxi takes 2 hours, and taxis leave every 10 minutes.

Taxis already on the route from X to Y: $\frac{120}{10}$
Taxis that start after from X to Y: $\frac{120}{10}$
Exclude the simultaneously departing taxi: $12 + 11 = 23$

Final Answer: 23 taxis.

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