An object is projected horizontally from a 100 m high cliff with a speed of 10 m/s. What will be its velocity 1 second after projection?10 m/s20 m/s10√2 m/s10√3 m/sSolution:Given: vx=10v_x = 10 m/s, g=10g = 10 m/s², t=1t = 1 s Vertical velocity: vy=gt=10v_y = g t = 10 m/s Resultant velocity: v=vx2+vy2=102+102=10√2 m/sv = \sqrt{v_x^2 + v_y^2} = \sqrt{10^2 + 10^2} = 14.1 \text{ m/s}
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