Solution:
\[ y = -\frac{g}{2 v_x^2} x^2 \]
This is of the form , which represents a parabolic path. Hence, the object follows a parabolic trajectory when viewed from the ground.
\[ y = -\frac{g}{2 v_x^2} x^2 \]
This is of the form , which represents a parabolic path. Hence, the object follows a parabolic trajectory when viewed from the ground.
Leave a Reply