Rankers Physics
Topic: Kinematics
Subtopic: Ground to Ground Projectile

A projectile is fired from level ground at an angle θ above the horizontal. The elevation angle Φ of the highest point as seen from the launch point is related to θ by the relation :
\[tan\phi=\frac{1}{4}tan\theta\]
\[tan\phi=tan\theta\]
\[tan\phi=\frac{1}{2}tan\theta\]
\[tan\phi=2tan\theta\]

Solution:

\[ tan \phi= H/2R= \frac{1}{2}tan\theta \]

Leave a Reply

Your email address will not be published. Required fields are marked *