When a car is stopped by applying brakes, it stops after travelling a distance of 80 m. If speed of car is halved and same retarding acceleration is applied then it stops after travelling a distance of20 m50 m75 m100 mSolution:Using the stopping distance formula: s∝u2s \propto u^2 If speed is halved, new stopping distance: s2=804=20 ms_2 = \frac{100}{4} = 25 \text{ m}
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