Rankers Physics
Topic: Kinematics
Subtopic: Equations of Motion

A car travelling with a velocity of 90 km/h slowed down to 54 km/h in 15 s. The retardation is
0.67 m/s²
1 m/s²
1.25 m/s²
1.5 m/s²

Solution:

Using the formula a=vfvita = \frac{v_f - v_i}{t}:

Converting to m/s:
9090 km/h = 2525 m/s, 5454 km/h = 1515 m/s.

a=152515=1015=0.67 m/s2a = \frac{15 - 25}{15} = \frac{-10}{15} = -0.67 \text{ m/s}^2

Retardation = 0.67 m/s².

Leave a Reply

Your email address will not be published. Required fields are marked *