A car travelling with a velocity of 90 km/h slowed down to 54 km/h in 15 s. The retardation is0.67 m/s²1 m/s²1.25 m/s²1.5 m/s²Solution:Using the formula a=vf−vita = \frac{v_f - v_i}{t}: Converting to m/s: 9090 km/h = 2525 m/s, 5454 km/h = 1515 m/s. a=15−2515=−1015=−0.67 m/s2a = \frac{15 - 25}{15} = \frac{-10}{15} = -0.67 \text{ m/s}^2 Retardation = 0.67 m/s².
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