Solution:
1. Movement 1: 30 m North
\[
\text{Displacement}_1 = 30 \hat{j}
\]
2. Movement 2: 20 m East
\[
\text{Displacement}_2 = 20 \hat{i}
\]
3. Movement 3: \(30\sqrt{2}\) m Southwest
\[
\text{Displacement}_3 = -30 \hat{i} - 30 \hat{j}
\]
Total Displacement:
\[
\text{Total Displacement} = (20 \hat{i} + 30 \hat{j}) + (-30 \hat{i} - 30 \hat{j}) = -10 \hat{i} + 0 \hat{j}
\]
Displacement = 10 m West
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