Rankers Physics
Topic: Kinematics
Subtopic: Distance and Displacement

A person moves 30 m north and then 20 m towards east and finally 30√2 min south -west direction. The displacement of the person from the origin will be
10 m along north
10 m along south
10 m along west
zero

Solution:

1. Movement 1: 30 m North
\[
\text{Displacement}_1 = 30 \hat{j}
\]

2. Movement 2: 20 m East
\[
\text{Displacement}_2 = 20 \hat{i}
\]

3. Movement 3: \(30\sqrt{2}\) m Southwest
\[
\text{Displacement}_3 = -30 \hat{i} - 30 \hat{j}
\]

Total Displacement:
\[
\text{Total Displacement} = (20 \hat{i} + 30 \hat{j}) + (-30 \hat{i} - 30 \hat{j}) = -10 \hat{i} + 0 \hat{j}
\]

Displacement = 10 m West

Leave a Reply

Your email address will not be published. Required fields are marked *