Solution:

1. Movement 1: 6 m North
\[
\text{Displacement}_1 = 6 \hat{j}
\]

2. Movement 2: 8 m East
\[
\text{Displacement}_2 = 8 \hat{i}
\]

3. Movement 3: 10 m Vertically Upwards
\[
\text{Displacement}_3 = 10 \hat{k}
\]

Total Displacement:
\[
\text{Total Displacement} = 6 \hat{j} + 8 \hat{i} + 10 \hat{k}
\]

 Magnitude of Displacement:

\[
|\text{Total Displacement}| = \sqrt{(8^2) + (6^2) + (10^2)} = \sqrt{64 + 36 + 100} = \sqrt{200} = 10\sqrt{2} \, \text{m}
\]