Solution:
\[ V_{av}=\frac{\int_{0}^{1}v.dt}{\int_{0}^{1}dt}= \frac{\int_{0}^{1}(t + 3).dt}{\int_{0}^{1}dt}=\frac{7}{2} m/s \]
If velocity of a particle is given by V = (t + 3) m/s, then average velocity in interval
0 ≤ t ≤ 1s is :
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