Rankers Physics
Topic: Electrostatics
Subtopic: Gauss's Law

Two parallel plates of infinite dimensions are uniformly charged. The surface charge density on one is \(\sigma_{A} \)and on the other is \(\sigma_{B}\), field intensity at point C will be Image related to
Proportional to \[\left( \sigma_{A}-\sigma_{B} \right)\]
Proportional to \[\left( \sigma_{A}+\sigma_{B} \right)\]
zero
\[2\sigma_{A}\]

Solution:

Net Electric Point at Point C will be directed downwards

\[ \overrightarrow{E}=\frac{\sigma_{A}}{2\varepsilon_{0}} + \frac{\sigma_{B}}{2\varepsilon_{0}}\]

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