Rankers Physics
Topic: Electrostatics
Subtopic: Electric Flux

The electric flux Φ through a hemisphere surface of radius R, placed in a uniform electric field of intensity E parallel to the axis of its circular plane is:
\[2\pi RE\]
\[2\pi R^{2}E\]
\[\pi R^{2}E\]
\[\left( 4/3 \right)\pi R^{3}E\]

Solution:

The electric flux through the hemisphere is due to the uniform electric field passing perpendicularly through the circular plane of radius \( R \).

Flux through the circular plane:
\[
\Phi = E \cdot \text{Area of circular plane} = E \cdot \pi R^2
\]

Since no flux passes through the curved surface (field is parallel to it), the total flux is:
\[
\Phi = \pi R^2 E
\]

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