NEET Physics Question - Electrostatics

A cylinder of radius R and length L is placed in a uniform electric field E parallel to the cylinder axis. The total flux from the surface of the cylinder is:

\[2\pi R^{2}E\]

\[\pi R^{2}E\]

\[\left( \pi R^{2}+\pi R^{2} \right)/E\]

zero

Solution:

Since the electric field \( E \) is parallel to the cylinder's axis, the field lines enter and exit symmetrically through the two flat circular ends. The curved surface has no perpendicular component of the field, so no flux passes through it.

By Gauss's law, the net flux through the entire surface is:
\[
\Phi = \text{Charge enclosed} / \varepsilon_0
\]

As no charge is enclosed, \( \Phi = 0 \).

Rankers Physics

Solution:

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