Solution:

The electric flux is given by:

\[
\Phi = \overrightarrow{E} \cdot \overrightarrow{S}
\]

Here, \(\overrightarrow{E} = 2\hat{i} + 4\hat{j} + 3\hat{k}\) and \(\overrightarrow{S} = 10\hat{j}\).

\[
\Phi = (2\hat{i} + 4\hat{j} + 3\hat{k}) \cdot (10\hat{j}) = 0 + 4 \cdot 10 + 0 = 40 \, \text{units}.
\]