NEET Physics Question - Electrostatics

Two conducting sphere s of radii R each are given charges +Q and –Q and are separated by a distance r (>2R). Th e force of attraction between them is \( \overrightarrow{F} \)If instead of charges +Q and –Q, we were to give them charges +Q each , the force of interaction between them would be

\[ \overrightarrow{F}\]

\[ - \overrightarrow{F}\]

direction opposite to \( \overrightarrow{F} \)but magnitude lesser than it

direction opposite to \( \overrightarrow{F} \) but magnitude more than it

Solution:

When the spheres have charges \( +Q \) and \( -Q \), they attract each other with force \( \overrightarrow{F} \).

If we replace \( -Q \) with \( +Q \), both spheres will have \( +Q \) charge, causing a repulsive force instead of attraction.

Since \( r > 2R \), there will be induced charges on the surfaces due to electrostatic induction, reducing the effective repulsive force compared to the attractive force \( \overrightarrow{F} \) in the initial configuration.

Conclusion:
The new force will be in the opposite direction to \( \overrightarrow{F} \) (repulsive) but with a magnitude less than \( F \) due to the effect of induced charges.

Rankers Physics

Solution:

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