A 6 kg box is travelling on ice at a speed of 9 m/s when a 12 kg packet is gently placed on it. The velocity will now be3 m/s4 m/s6 m/s8 m/sSolution:From Principal of conservation of momentum m 1 v 1 = (m 1 + m 2 ) v 6 × 9 = ( 6 + 12) × v ⇒ v = 3 m/s
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