Solution:
\[ x_{cm}= \frac{(m_{1}x_{1} + m_{2}x_{2})}{m_{1}+m_{2}} \]
\[ x_{cm}= \frac{12(0)+ 16 (1.2 × 10^{–10})}{12+16}= 0.69 \times 10^{–10} m \]
In carbon monoxide molecules, the carbon and the oxygen atoms are separated by a distance of 1.2 × 10 –10 m. The distance of the centre of mass from the carbon atom is
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