Nucleus: Practice Problem & Solution

Assertion (A): The binding energy per nucleon, for nuclei with atomic mass number \( A > 100 \) decreases with \( A \). Reason (R): The nuclear forces become weaker for heavier nuclei.

Both (A) & (R) are true and the (R) is the correct explanation of the (A)

Both (A) & (R) are true but the (R) is not the correct explanation of the (A)

(A) is true but (R) is false

Both (A) and (R) are false

Solution Explained:

To solve this problem, we apply the core principles of Nucleus. Understanding the underlying formula is key to arriving at the correct answer below:

The binding energy per nucleon peaks around \( A=60 \) and decreases for heavier nuclei due to increasing Coulomb repulsion, which effectively weakens the average nuclear force per nucleon. Both (A) and (R) are true, and (R) correctly explains (A).

Nucleus: Practice Problem & Solution

Solution Explained:

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