NEET Physics Question - Modern Physics

Assertion (A): \( \text{Fe}^{56} \) nucleus is more stable than \( \text{U}^{235} \) nucleus.

Reason (R): Binding energy of \( \text{Fe}^{56} \) nucleus is more than binding energy of \( \text{U}^{235} \).

Both (A) & (R) are true and the (R) is the correct explanation of the (A)

Both (A) & (R) are true but the (R) is not the correct explanation of the (A)

(A) is true but (R) is false

Both (A) and (R) are false

Solution:

\( \text{Fe}^{56} \) has the highest binding energy per nucleon, making it the most stable. So (A) is true. The total binding energy of \( \text{U}^{235} \) is much higher than \( \text{Fe}^{56} \) due to its larger number of nucleons. Thus (R) is false.

Rankers Physics

Nuclear Stability and Binding Energy

Solution:

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