De Broglie Hypothesis and Energy – Rankers Physics
Topic: Modern Physics
Subtopic: Photoelectric Effects and deBroglie Equation

De Broglie Hypothesis and Energy

Assertion (A): By de-Broglie hypothesis, \(p = h/\lambda\) for both the electron and the photon.
Reason (R): If an electron has the same wavelength as a photon, they have the same energy.
 
Both (A) & (R) are true and the (R) is the correct explanation of the (A)
Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
(A) is true but (R) is false
Both (A) and (R) are false

Solution:

Concept: De Broglie wavelength and energy relations.
Formula: De Broglie wavelength \(\lambda = h/p\). Photon energy \(E_p = pc = hc/\lambda\). Electron kinetic energy \(E_e = p^2/(2m) = h^2/(2m\lambda^2)\) (non-relativistic).
Solution: De Broglie's hypothesis states that momentum \(p = h/\lambda\) applies to all particles, including electrons and photons. So (A) is true. If an electron and a photon have the same wavelength, their energies are \(E_p = hc/\lambda\) and \(E_e = h^2/(2m\lambda^2)\), which are generally not equal. So (R) is false.

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