Diffraction from a Wide Slit – Rankers Physics

Diffraction: Practice Problem & Solution

Assertion (A): We cannot get diffraction pattern from a wide slit illuminated by monochromatic light. Reason (R): In diffraction pattern, all the bright bands are not of the same intensity.  
Both (A) & (R) are true and the (R) is the correct explanation of the (A)
Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
(A) is true but (R) is false
Both (A) and (R) are false

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Diffraction. Understanding the underlying formula is key to arriving at the correct answer below:

Assertion (A) is true in a practical sense; a very wide slit (\(a \gg lambda\)) yields a pattern with very small angular spread, making it indiscernible. Reason (R) is true; the intensity of secondary maxima decreases rapidly. (R) does not explain (A).

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Similar Practice Questions

Explore conceptually related problems to test your knowledge.

1. A screen is placed \(50\text{ cm}\) from a single slit, which is illuminated with \(6000\text{ A^0}\) light. If distance between the first and third minima in the diffraction pattern is \(3\text{ mm}\), the width of the slit is
2. Assertion (A): We cannot get diffraction pattern from a wide slit illuminated by monochromatic light. Reason (R): In diffraction pattern, all the bright bands are not of the same intensity.  
3. Assertion (A): Diffraction is common in sound but not common in light waves. Reason (R): Wavelength of light wave is more than the wavelength of sound.  
4. Assertion (A): Wave nature can be proved by phenomena of interference and diffraction. Reason (R): Only transverse wave can show the phenomena of polarization.
5. Assertion (A): Resolving power of a microscope is different for different colours of illuminating light. Reason (R): Resolving power of a microscope is directly proportional to the wavelength of illuminating light.