Solution:
Using equation of motion
v= u + at
⇒ 0= 6 + a ×10
⇒ a= -0.6 m/sec^2
Maximum Friction force is μN = μ mg so, a= μ.g
⇒ -0.6 = - μ. 10
⇒μ = 0.06
A marble block of mass 2 kg lying on ice when given a velocity of 6 ms-1 is stopped by friction in 10 s. Then the coefficient of friction is
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